The resistivity of some material is 2.34 ´ 10-7 Wm at 20.0 degrees of Celsius.?
The resistivity of some material is 2.34 ´ 10-7 Wm at 20.0 degrees of Celsius. The
resistivity of the same material becomes 5.88 ´ 10-7 Wm. If the temperature coefficient is
0.0134 (oC)-1, what is the final temperature?
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5.88 * 10^-7 = 2.34 * 10^-7 * [1 + 0.0134(t - 20)]
=> t = 20 + (1/0.0134) * [ 5.88/2.34 - 1] °C
=> t = 132.9° C.