The position function x(t) of a particle moving along an x axis is x = 4.7 − 5.4t2, with x in meters and t in seconds.?
(a) At what time does the particle (momentarily) stop?
(b) Where does the particle (momentarily) stop?
(c) At what negative time does the particle pass through the origin?
(d) At what positive time does the particle pass through the origin?
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The velocity is the time derivative of this, or v = -5.4*2t
a) When v = 0. Set v equal to 0. Solve for t.
b) Plug that value of t into the equation for x.
c) When x = 4.7 - 5.4t^2 = 0. That's a simple quadratic equation. Solve it.
d) The positive solution to the above equation.
Which of these simple equations is troubling you?