x^4+6x^3-3x^2+24x-28 = ( x ^2 + 6x -7)(x^2+4) (you are able to receive the climate via assuming x^4+6x^3-3x^2+24x-28=(x^2+bx+c)(x^2+dx+d... and equate the coefficients the place you have 4 equations and four unknowns) zeros implies looking x for which f(x)=0, ( x ^2 + 6x -7)(x^2+4)=0 =>x=-7/a million/ ±2i so the complicated zeros are ±2i
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Verified answer
Just factor the 3 out of x^2 + 24x, and complete the square.
y = 3(x^2 + 8x) + 47
y = 3(x^2 + 8x + 16 - 16) + 47
y = 3(x^2 + 8x + 16) - 16*3 + 47
y = 3(x+4)^2 - 16*3 + 47
You can simplify it from here.
y = 3x² + 24x + 47 = 3 (x² + 8x + 16) - 1 = 3 (x + 4)² - 1
Therefore a = 3, h = -4 and k = -1
x^4+6x^3-3x^2+24x-28 = ( x ^2 + 6x -7)(x^2+4) (you are able to receive the climate via assuming x^4+6x^3-3x^2+24x-28=(x^2+bx+c)(x^2+dx+d... and equate the coefficients the place you have 4 equations and four unknowns) zeros implies looking x for which f(x)=0, ( x ^2 + 6x -7)(x^2+4)=0 =>x=-7/a million/ ±2i so the complicated zeros are ±2i