The measures of the angles in ∠ABC are in the extended ratio 4:5:6. Find the measure of the angles of the triangle.
Can anyone help me with this?
the sum of the angles in a triangle = 180
use the numbers of the ratio as the coefficients of x:
4x+5x+6x = 180; 15x = 180; x = 12
now just substitute x into the terms:
angle1 = 4(12) = 48
angle2 = 5(12) = 60
angle3 = 6(12) = 72
well a triangle has 180 degrees,
so one of them has to be 60 degrees (ratio 5)
and the other 2 just add/substract 12 so its
48:60:72.
First You should understand that this forum is not math friendly.. its difficult to explain or write with symbols .
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the sum of the angles in a triangle = 180
use the numbers of the ratio as the coefficients of x:
4x+5x+6x = 180; 15x = 180; x = 12
now just substitute x into the terms:
angle1 = 4(12) = 48
angle2 = 5(12) = 60
angle3 = 6(12) = 72
well a triangle has 180 degrees,
so one of them has to be 60 degrees (ratio 5)
and the other 2 just add/substract 12 so its
48:60:72.
First You should understand that this forum is not math friendly.. its difficult to explain or write with symbols .