A projectile is shot straight up from the earth's surface at a speed of 1.20×10^4 km/hr
v = 1.20E4/3.6 = 0.333E4 m/s
Assuming no aerodynamic drag:
For speeds such as these, the formulae for gravitational PE must be used:
Rmax = 2*G*M*R/[2*G*M - v²*R] where R is the earth's radius and M her mass.
Rmax = 6.996E6 m
Hmax = Rmax - R = 0.62E6 m = 620 km
Depends on it's shape, and weight also the type of propellant
Copyright © 2024 1QUIZZ.COM - All rights reserved.
Answers & Comments
v = 1.20E4/3.6 = 0.333E4 m/s
Assuming no aerodynamic drag:
For speeds such as these, the formulae for gravitational PE must be used:
Rmax = 2*G*M*R/[2*G*M - v²*R] where R is the earth's radius and M her mass.
Rmax = 6.996E6 m
Hmax = Rmax - R = 0.62E6 m = 620 km
Depends on it's shape, and weight also the type of propellant