The magnitude of a velocity vector is called speed. Suppose that a wind is blowing from the direction N45°W at a speed of 30 km/h. (This means that the direction from which the wind blows is 45° west of the northerly direction.) A pilot is steering a plane in the direction N60°E at an airspeed (speed in still air) of 150 km/h. The true course, or track, of the plane is the direction of the resultant of the velocity vectors of the plane and the wind. The ground speed of the plane is the magnitude of the resultant. Find the true course and the ground speed of the plane. Give your answers correct to one decimal place.
(a) N _____E (true course)?
(b) ____ km/h (ground speed)?
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Verified answer
Actually, the wind is blowing TO S45ºE, and the resultant is the SUM of the wind vector (as inverted above) and the aircraft vector.
Vpx = 150 cos 30
Vpy = 150 sin 30
Vwx = 30 cos 45
Vwy = –30 sin 45
Add the x and y components to get Rx and Ry
R = √(Rx² + Ry²)
θ = arctan (Ry/Rx)