The latent heat of vaporizaiton of H2O at body temperature (37.0°C) is 2.42 106 J/kg. To cool the body of a?
75 kg jogger (average specific heat capacity = 3500 J/(kgC°) by 1.5 C°, how many kilograms of water in the form of sweat have to be evaporated?
I tried using the formula Q=mL and mLf=cm(change)T
Update:Well Mary, I have been trying to figure it out for a week now and I'm using my last resort (yahoo) to try and understand these concepts, how they apply to the questions asked, and how to solve the problem.. So please keep your snide comments to yourself.
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energy cooling jogger:
(mass jogger)x(specific heat capacity)x(change in temp)
=
(mass water)(heat of vaporization).
Everything is given to you except mass of water. Solve for it.
H2o Body