Choices:
y = (x – 2)2 – 1
y = (x + 2)2 – 1
y = (x – 1)2 – 2
y = (x + 1)2 – 2
Each of the given choices is in vertex form → y = a(x - h)² + k where (h, k) is the vertex
for each case a = 1
the required vertex is at (-2, -1)
the required equation is y = (x - -2)² + -1 ... [subsing into the vertex form of the equation]
so y = (x + 2)² - 1 →→ so the 2nd choice
the vertex is -b/2a
so get rid of the brackets and see which one will give you (-2,-1)
Lol jus finished learning dis chapter....I would luv to help u but since I can't get photos I can't soz...... Strange thing but this question is the same question as my book ...by any chance r u my classmate o.o ........Alexander?
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Answers & Comments
Each of the given choices is in vertex form → y = a(x - h)² + k where (h, k) is the vertex
for each case a = 1
the required vertex is at (-2, -1)
the required equation is y = (x - -2)² + -1 ... [subsing into the vertex form of the equation]
so y = (x + 2)² - 1 →→ so the 2nd choice
the vertex is -b/2a
so get rid of the brackets and see which one will give you (-2,-1)
Lol jus finished learning dis chapter....I would luv to help u but since I can't get photos I can't soz...... Strange thing but this question is the same question as my book ...by any chance r u my classmate o.o ........Alexander?