The freezing point of benzene C6H6 is 5.50°C at 1 atmosphere. A nonvolatile, nonelectrolyte that dissolves in benzene is estrogen (estradiol).
If 11.65 grams of estrogen, C18H24O2 (272.4 g/mol), are dissolved in 154.1 grams of benzene ...
The molality of the solution is
m.
The freezing point of the solution is
°C.
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Answers & Comments
(11.65 g C18H24O2) / (272.4 g C18H24O2/mol) / (0.1541 kg) = 0.2775 mol/kg = 0.2775 m C18H24O2
(5.12 °C/m) x (0.2775 m) = 1.42°C change
5.50°C - 1.42°C = 4.08°C
same as your question here
https://answers.yahoo.com/question/index?qid=20180...
except we use this equation instead
.. dTfp = kf * m * i
where
.. dTfp = change in bp = bp pure solvent - bp solution..... .. . <----- note the difference !!!!
.. kf = cryoscopic constant (freezing point depression constant) for the solvent
... .m = molality = moles solute / kg solvent
.. . i = van't hoff factor = # ions 1 particle dissociates into in solution