Reverse the 3rd equation, change the sign of ∆H°, and then add the three equations:
H2(g) + 1/2O2(g) =⇒ H2O(l ) ∆H° = -286kJ
Ca(s) + 2H+ =⇒ Ca2+(aq) + H2(g) ∆H° -544 kJ
Ca2+(aq) + H2O(l) =⇒ CaO(s) + 2H+ ∆H° = +193 kJ
Ca(s) + 1/2O2(g) ==⇒ CaO(s) ∆H° = -637 kJ
They may be given, but you can't read them. If you are too lazy to write the question so that it can be read, then .....
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Reverse the 3rd equation, change the sign of ∆H°, and then add the three equations:
H2(g) + 1/2O2(g) =⇒ H2O(l ) ∆H° = -286kJ
Ca(s) + 2H+ =⇒ Ca2+(aq) + H2(g) ∆H° -544 kJ
Ca2+(aq) + H2O(l) =⇒ CaO(s) + 2H+ ∆H° = +193 kJ
Ca(s) + 1/2O2(g) ==⇒ CaO(s) ∆H° = -637 kJ
They may be given, but you can't read them. If you are too lazy to write the question so that it can be read, then .....