Verified answer

Add all the resistances up since they are in series.

You get R = 90 ohms.

V(battery) = I * R

Since the current is the same around a closed loop, I = 0.13 A

V(battery) = 11.7 Volts

Since the current through the resistors must be the same (current entering a connecting point must equal current exiting that point), we know the current is the same. We can calculate the voltage developed across each resistor and add them. We also can add the resistances (52 + 38 = 90) and then calculate the total voltage developed across them. It will be equal to the terminal voltage at the battery.

Using Ohm's law, E = I * R, we take 90 and multiply it by 0.13 Amp. This yields 11.7, which is the answer to the question in Volts.

Best regards,

Jim