Verified answer

Hello,

Just remember that for any real values a, b and c:

∫ (a→c) f(x).dx = ∫ (a→b) f(x).dx   +   ∫ (b→c) f(x).dx

∫ (a→b) f(x).dx = - ∫ (b→a) f(x).dx

∫ (a→a) f(x).dx = 0

Since you have:

∫ (0→1) f(x).dx = 3

∫ (0→3) f(x).dx = 2

∫ (1→3) f(x).dx = ∫ (1→0) f(x).dx   +    ∫ (0→3) f(x).dx

   = -∫ (0→1) f(x).dx   +    ∫ (0→3) f(x).dx

   = -3 + 2

   = -1

∫ (3→1) f(x).dx = -∫ (1→3) f(x).dx

   = -(-1)

   = 1

∫ (2→2) f(x).dx = 0

∫ (2→3) 2.f(x).dx

cannot be calculated from the provided data.

Regards,

Dragon.Jade :-)