If star A has a temperature of 5,800 K, what is the temperature of star B?
Wien's law:
λmax × T = 2.8978 x 10^6 nm K
750nm x T = 2.8978 x 10^6 nm K
T = (2.8978 x 10^6 nm K)/750nm
T = 3863.7 K
Copyright © 2024 1QUIZZ.COM - All rights reserved.
Answers & Comments
Wien's law:
λmax × T = 2.8978 x 10^6 nm K
750nm x T = 2.8978 x 10^6 nm K
T = (2.8978 x 10^6 nm K)/750nm
T = 3863.7 K