Solve the system of equations by the substitution or addition method.
{(x+y)/2+x=12
{(x-y)/2-y=-6
(x,y)=?
⇔
{x/2 + y/2 + x = 12
{x/2 - y/2 - y = - 6
{3x/2 + y/2 = 12
{x/2 - 3y/2 = - 6
{3x + y = 24
{x - 3y = - 12
From 2nd equation, we have x = 3y - 12. Substitute to 1st equation:
3(3y - 12) + y = 24
9y - 36 + y = 24
10y = 24 + 36
y = 6
Then x = 3*6 - 12 = 6
Answer: (x, y) = (6, 6)
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{(x+y)/2+x=12
{(x-y)/2-y=-6
⇔
{x/2 + y/2 + x = 12
{x/2 - y/2 - y = - 6
⇔
{3x/2 + y/2 = 12
{x/2 - 3y/2 = - 6
⇔
{3x + y = 24
{x - 3y = - 12
From 2nd equation, we have x = 3y - 12. Substitute to 1st equation:
3(3y - 12) + y = 24
9y - 36 + y = 24
10y = 24 + 36
y = 6
Then x = 3*6 - 12 = 6
Answer: (x, y) = (6, 6)