Verified answer

1. Divide by sqrt(3)

sec(2x) = 2/sqrt(3).............now write in terms of cosine

cos(2x) = sqrt(3)/2

If you have cosA = sqrt(3)/2, A = pi/6 and 11pi/6 on the interval [0, 2pi).

So A = 2x = pi/6 and 11pi/6 so x = pi/12 and 11pi/12.

√3 sec 2x =2

√3 /cos2x =2

cos 2x = √3 / 2

2 x = 2 pi n +/- pi/6 where n = 0,1,2,3

x = pi n +/- pi/12 or

x = pi( n +/- 1/12) where n = 0,1,2,3

x = pi/12, 11 pi/12, 13 pi/12, 23/pi/12

What are the variables?