Find the Slope of the tangent to the graph of f at a general point x○?
f(x) = x^2 + 1; x○=2
(x○ means 'x not' )
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f(x) = x^2 + 1; x○=2
(x○ means 'x not' )
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f(x) = x^2 + 1; x○=2
Slope = f'(x) = 2x
At xo=2
f'(2)=4
Slope of the tangent is 4.