Verified answer

(3x + 3)² - 36 = 0

x = +/-6 - 3 /(3)

x = 2 - 1 = 1

x = -2 - 1 = -3

we've been taught a diverse technique, p.c.. whichever is least puzzling for you. c^2 + 4c - (the volume right here's 1/2 the middle time period, i.e. 4, then sqaured) - 7 (then - a similar time period in the different brackets) = 0 c^2 + 4c + 4 -7 - 4 = 0 (c+2)^2 -7 - 4 = 0 (The time period contained in the brackets is 1/2 the middle time period, supplying you with a desirable sq.) (c+2)^2 -11 = 0 (c + 2 + sqrt11)(c + 2 - sqrt11)=0 (Factorise the equation to get this, a distinction of two squares) c=-2 +- sqrt11 Use the null aspect regulation to get your answer.

9x²+18x–27=0

x²+2x–3 = 0

(x+3)(x–1) = 0

x = 1, –3

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9x^2 + 18x - 27 = 0

9x^2 + 18x = 27

x^2 + 2x = 3

x^2 + 2x + 1 = 3 + 1

(x + 1)^2 = 4

x + 1 = +/- 2

x = -1 +/- 2

x = -3 , 1

9x^2+18x-27=0

9(x^2+2x-3)=0

9(x+3)(x-1)=0

x={-3,1}