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6 – 3(–2 – 4x) = 2(3(x – 4) + 7)

distribute the (-3) on the left to get a (+6 and +12x). distribute the (+3) on the right to get (3x-12)

6+6+12x= 2(3x-12+7)

on the left, 6+6 is 12, distribute the (2) on the right to get (6x-24+14)

12+12x=6x-24+14

on the right, (-24)+14 is (-10)

12+12x=6x-10

subtract 12 from both sides to cancel it out

12x=6x-22

subtract 6x from both sides to cancel it out

6x=-22

divide both sides by 6

x=-3.66 continuing or -22/6

Your answer number 1 and 3 are wrong because you can't get 24 from a 12 and 10.

The number 2 answer forgot to distribute the (-3) to the 4x to get 12x in the beginning.

Good luck!

6 + 6 + 4x = 6x - 24 + 14

12 + 4X = 6X - 10

2X = 22

X = 11

6 + 6 + 12x = 6x - 10

6x = -22

x = -22/6 =-11/3

6+6+12x= 2(3x-12+7)

12+12x=6x-24+14

12+12x=6x-10

24= -6x

x= -4

6+6+12x= 2(3x-12+7)

12+12x=6x-24+14

12+12x=6x-10

24= -6x

x= -4