Solve the equation 4^(x + 2) = 8^(x – 1).
4^(x + 2) = 8^(x – 1)
2^2(x + 2) = 2^3(x - 1)
2(x + 2) = 3(x - 1)
2x + 4 = 3x - 3
2x - 3x = - 3 - 4
- x = - 7
x = 7 answer//
I'd break down 4 and 8 to be powers of 2
4=2^2 8=2^3
2^2(x+2) = 2^3(x-1)
Now, you can just forget about the 2^
So,
2(x+2)=3(x-1)
Distribute & Solve
2x+4=3x-3
-2x -2x
4=x-3
+3 +3
7 = x
So, x=7
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Verified answer
4^(x + 2) = 8^(x – 1)
2^2(x + 2) = 2^3(x - 1)
2(x + 2) = 3(x - 1)
2x + 4 = 3x - 3
2x - 3x = - 3 - 4
- x = - 7
x = 7 answer//
I'd break down 4 and 8 to be powers of 2
4=2^2 8=2^3
2^2(x+2) = 2^3(x-1)
Now, you can just forget about the 2^
So,
2(x+2)=3(x-1)
Distribute & Solve
2x+4=3x-3
-2x -2x
4=x-3
+3 +3
7 = x
So, x=7