Substitution ability you're taking between the variables in one equation and replace it in the different. Or, y = 3x + 2 in one equation, so which you would be able to easily plug the 3x + 2 into the different equation to remedy for x: 2x + y = 5 is going to 2x + (3x + 2) = 5 2x + 3x + 2 = 5x + 2 = 5 remedy for x: 5x = 5 - 2 = 3 x = 3/5 then you could placed the value you chanced on for x into the two equation to discover y: y = 3x + 2 is going to y = 3 (3/5) + 2. y = 9/5 + 2 y = 9/5 + 10/5 y = 19/5 so... x = 3/5 and y = 19/5
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See if this helps: Rule: When you move a term across an equal sign remember to change its sign from + to a minus or from a - to a +
Solving for y means y must remain by itself on one side of the = sign and be a +y
So if you move -y across the= sign to the right side and change its sign the equation becomes:
2x = 2 + y then move the +2 across the = sign to the left side and change its sign
2x -2 = y solved!
With a little practice you can do this very quickly in your head.
Substitution ability you're taking between the variables in one equation and replace it in the different. Or, y = 3x + 2 in one equation, so which you would be able to easily plug the 3x + 2 into the different equation to remedy for x: 2x + y = 5 is going to 2x + (3x + 2) = 5 2x + 3x + 2 = 5x + 2 = 5 remedy for x: 5x = 5 - 2 = 3 x = 3/5 then you could placed the value you chanced on for x into the two equation to discover y: y = 3x + 2 is going to y = 3 (3/5) + 2. y = 9/5 + 2 y = 9/5 + 10/5 y = 19/5 so... x = 3/5 and y = 19/5
You subtract 2x from both sides, giving you this
-y=2-2x
Then you make everything negative in order to get the y positive, giving you
y=-2+2x
This is as far as you can go because you cannot solve for two variables in the same equation.
2x -y +y = 2+y
2x=2+y
2x-2=y
2x-y-2=2-2 rite? then
2x-y-2=0
2x-y-2+y=y
2x-2=y
so y=2x-2.
y = 2x - 2 ... there's not much else you can do...