Verified answer

4(x - 1) + 2 = 3x + 8 - 2x

4x - 4 + 2 = x + 8

4x - 2 = x + 8

3x - 2 = 8

3x = 10

x = 10/3

X=-10

This one is elementary. :) First, you want to precise both words interior a similar bases(it is 2 for this reason). 2^(3x+2)=8^(-2x+a million) will change into 2^(3x+2)=2^3(-2x+a million) because 8 = 2^3 because the bases are equivalent, you could say that the exponents are equivalent as well. for this reason, you've 3x + 2 = 3(-2x + a million) then you definitely purely ought to scrub up for x. 3x + 2 = -6x + 3 9x = a million x = a million/9 << answer :)

4x-4+2=3x+8-2x

4x-2=x+8

4x-x=8+2

3x=10

x=10/3

x=3.33 or 3 1/3

Solve for x:

4(x-1)+2=3x+8-2x

Distribute[4(x-1)]:

4x-4+2=3x+8-2x

Combine Like Terms[3x and -2x]:

4x-4+2=x+8

Combine Like Terms[-4 and 2]:

4x-2=x+8

Subtract either "x" or "4x" to both sides. I'll pick "x":

3x-2=8

Add 2 to both sides:

3x=10

Divide 3 to both sides:

So x is:

x=3.33(repeating)

OR in fraction form:

x=10/3

4x-4+2 = 3x + 8 - 2x

4x - 3x + 2x = 8 - 2 + 4

3x = 10

x = 10/3

distribute

4x-4+2=3x+8-2x

combine like terms

4x-2=x+8

get x's to one side, constants to other by subtraction and addition

3x=10

divide both sides by 3

x=10/3 = 3 and 1/3

check your answer:

plug in to original equation

4[(10/3)-1]+2=3(10/3)+8-2(10/3)

4(7/3)+2=10+8-20/3

34/3=30/3+24/3-20/3(true)

to solve for x:

1) repeating problem: 4(x - 1) + 2 = 3x + 8 - 2x

2) multiply left side by 4 = distribute the 4, and on the right side combine the x's: 4x - 4 + 2 = x + 8

3) add the -4 and +2 on the left side: 4x - 2 = x + 8

4) subtract the x (from the right side) from both sides and add 2 (opposite of -2) to both sides: 3x = 10

5) divide by 3 on both sides to get x by itself: x = (10/3)

x= 10/3

4x - 4 + 2 = 3x + 8 - 2x

4x - 2 = 8 + x

3x = 10

x = 3.3 repeating