Verified answer

5(x-1)-(x+5)=2,

5x-5-x-5=2,

5x-x-5-5=2,

4x-10=2,

4x=2+10,

4x=12,

x=12/4,

x=3.

Answer: 3.

Can someone answer my question?

Apply the distributive property.

5x-5-x-5=2

Combine the like terms.

4x-10=2

Solve for x.

4x=12

x=3

Distribute the five inside the first set of parentheses:

5x - 5 - (x + 5) = 2

Distribute the negative inside the remaining parentheses:

5x - 5 - x - 5 = 2

Combine like terms on the left:

4x - 10 = 2

Add 10 to both sides:

4x = 12

Divide both sides by 4; x = 3.

5(x - 1) - (x + 5) = 2

Use the Distributive Property on the LHS (Left Hand Side)

5x - 5 - x - 5 = 2

Collect like terms (variables to your left, constants to your right)

5x - x = 2 + 5 + 5

4x = 12

Divide both sides by 4 to isolate the variable

x = 3

Then, check your work to see if the LHS of the original equation equals the RHS when substituted for the variable (x = 3)

5(x - 1) - (x + 5) = 2

LHS RHS

5(x - 1) - (x + 5) 2

5(3 - 1) - (3 + 5)

5(2) - 8

10 - 8

2

LHS = RHS (You can dance)

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