A) no answer (not one of the solutions ARE ultimate (-2, -5) a million) y=x2+3x+5 y=5x+5 2) (5x+5)=-5 5x= -10 x=-2 So, you plug in x (-2) to discover the fee of y y= (-2)2+3(-2)+5 y=-4-6+5 y= -5 the respond is x= -2, y= -5, aka (-2,-5) determination A.) does not be ultimate, because of the fact there's a answer and you will discover it. the final answer might desire to be (-2,-5) or not one of the ABOVE, all solutions are incorrect!
Answers & Comments
Verified answer
∫x2-3x-1/x3+x2-2x dx
=∫x^2dx-∫3xdx-∫x^(-3)dx+∫x^2dx-∫2xdx
=[∫x^2dx+∫x^2dx]+[-∫3xdx--∫2xdx]-∫x^(-3)dx
=∫(x^2+x^2)dx-[∫(3x+2x)dx-∫x^(-3)dx
=∫2x^2dx-∫5dx-∫x^(-3)dx
=2∫x^2dx-5∫dx-∫x^(-3)dx
=2/(2+1)x^(2+1)-5/(1+1)x^(1+1)-1/(-3+1)x^(-3+1)+constant
=2/3x^3-5/2x^2+1/2x^(-2)+constant
the formula ∫ax^ndx=a/(n+1)x^(n+1)+constant ( n is not -1) should be used
A) no answer (not one of the solutions ARE ultimate (-2, -5) a million) y=x2+3x+5 y=5x+5 2) (5x+5)=-5 5x= -10 x=-2 So, you plug in x (-2) to discover the fee of y y= (-2)2+3(-2)+5 y=-4-6+5 y= -5 the respond is x= -2, y= -5, aka (-2,-5) determination A.) does not be ultimate, because of the fact there's a answer and you will discover it. the final answer might desire to be (-2,-5) or not one of the ABOVE, all solutions are incorrect!