Solve For Θ
0 ≤ Θ < 360
sino^2 - 2sino = 3
==> sino^2 - 2sino -3 = 0
think of it as a quadratic function.. let x=sino
x^2 - 2x - 3 = 0
(x-3)(x+1) = 0
so..
x=3 or x=-1
sino = 3 or sino = -1
**sino cant be = 3 since we only have a unit circle, so it's not included..
sino = -1
o = 3pi/2
^_^V
Let x = sin θ
x² - 2x - 3 = 0
(x - 3) (x + 1) = 0
x = 3 , x = - 1
Accept x = - 1 only
sin θ = - 1
θ = 270°
Again its a quadratic in sin theta
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Verified answer
sino^2 - 2sino = 3
==> sino^2 - 2sino -3 = 0
think of it as a quadratic function.. let x=sino
x^2 - 2x - 3 = 0
(x-3)(x+1) = 0
so..
x=3 or x=-1
sino = 3 or sino = -1
**sino cant be = 3 since we only have a unit circle, so it's not included..
sino = -1
o = 3pi/2
^_^V
Let x = sin θ
x² - 2x - 3 = 0
(x - 3) (x + 1) = 0
x = 3 , x = - 1
Accept x = - 1 only
sin θ = - 1
θ = 270°
Again its a quadratic in sin theta