√(x^2+2x+1)
=√(x^2+2x+1)
=√[(x+1)(x+1)]
=√[(x+1)^2]
=x+1
= â(x² + 2x + 1)
= â(x + 1)(x + 1)
= â(x + 1)²
= x + 1
.
(x+1)
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Verified answer
√(x^2+2x+1)
=√(x^2+2x+1)
=√[(x+1)(x+1)]
=√[(x+1)^2]
=x+1
= â(x² + 2x + 1)
= â(x + 1)(x + 1)
= â(x + 1)²
= x + 1
.
(x+1)