pls simplify. :(
replace sinΘ ; cosΘ with m ; n
m^2+n^2+2mn+m^2+n^2-2mn = 2m^2+2n^2 = 2(m^2+n^2)
since (sin^2Θ+cos^2Θ) = 1, then 2*1 = 2
Here's my best attempt: I grouped the similar numbers and sorted them according to their ASCII order =) Best of luck!
22
((
))
^^
+
-
cos cos
sin sin
ΘΘΘΘ
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replace sinΘ ; cosΘ with m ; n
m^2+n^2+2mn+m^2+n^2-2mn = 2m^2+2n^2 = 2(m^2+n^2)
since (sin^2Θ+cos^2Θ) = 1, then 2*1 = 2
Here's my best attempt: I grouped the similar numbers and sorted them according to their ASCII order =) Best of luck!
22
((
))
^^
+
-
cos cos
sin sin
ΘΘΘΘ