sin(x - y) = sin(x)cos(y) - cos(x)sin(y)
Then, since x = π and y = θ..
sin(π - θ) = sin(π)cos(θ) - cos(π)sin(θ)
= (0)cos(θ) - (-1)sin(θ)
= sin(θ)
I hope this helps!
OK. Just look up your formulas for sin(a-b) and plug in. sin(pi)cos(theta)-sin(theta)cos(pi)
sinÏcosθ - sinθcosÏ
Since sinÏ=0, and cosÏ=1
final answer is
sin(Ï-θ)= -sinθ
sinpicoso-cospi sino
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sin(x - y) = sin(x)cos(y) - cos(x)sin(y)
Then, since x = π and y = θ..
sin(π - θ) = sin(π)cos(θ) - cos(π)sin(θ)
= (0)cos(θ) - (-1)sin(θ)
= sin(θ)
I hope this helps!
OK. Just look up your formulas for sin(a-b) and plug in. sin(pi)cos(theta)-sin(theta)cos(pi)
sinÏcosθ - sinθcosÏ
Since sinÏ=0, and cosÏ=1
final answer is
sin(Ï-θ)= -sinθ
sinpicoso-cospi sino