Since sin^2θ + cos^2θ = 1, we see that:
sin^2θ = 1 - cos^2θ, by solving for sin^2θ.
So, substituting in sin^2θ for 1 - cos^2θ yields:
(1 - cos^2θ)/(1 + cos^2θ) = sin^2θ/(1 + cos^2θ).
I hope this helps!
There are some other ways to put it listed if you scroll down to alternative forms.
http://www.wolframalpha.com/input/?i=%281-cos%C2%B...
(1 - cos²(θ))/(1 + cos²(θ)) = (sin²(θ))/(2 - sin²(θ))
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Since sin^2θ + cos^2θ = 1, we see that:
sin^2θ = 1 - cos^2θ, by solving for sin^2θ.
So, substituting in sin^2θ for 1 - cos^2θ yields:
(1 - cos^2θ)/(1 + cos^2θ) = sin^2θ/(1 + cos^2θ).
I hope this helps!
There are some other ways to put it listed if you scroll down to alternative forms.
http://www.wolframalpha.com/input/?i=%281-cos%C2%B...
(1 - cos²(θ))/(1 + cos²(θ)) = (sin²(θ))/(2 - sin²(θ))