Verified answer

Ola Bruno jose

a) (9 - x²) / (x² - 6x + 9) = -(x - 3)*(x + 3)/(x - 3)² = -(x + 3)/(x - 3)

b) (x³ - 2x² - x + 2) / (x² - 1) = (x - 2)*(x² - 1)/(x² - 1) = x - 2

c) 1/x² - 1/16 = (1/x + 1/4)*(1/x - 1/4)

d) (1/x + h - 1/x)/h = h/h = 1

pronto