f(x+1) = x*f(x) e f(1/2) = √π
.
x + 1 = 3/2
2x + 2 = 3
2x = 1
x = 1/2
f(1/2 + 1) = 1/2*f(1/2)
f(3/2) = 1/2*√π
f(3/2) = √π/2
f(x + 1) = x*f(x)
f(x) = k*x! (função fatorial)
f(1/2) = k*(1/2)! = k*âÏ/2 = âÏ --> k = 2
f(x) = 2*x!
f(3/2) = 2*(3/2)!
(3/2)! = 3âÏ/4
f(3/2) = 2*3âÏ/4 = 3âÏ/2
pronto
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Verified answer
f(x+1) = x*f(x) e f(1/2) = √π
.
.
.
x + 1 = 3/2
2x + 2 = 3
2x = 1
x = 1/2
f(1/2 + 1) = 1/2*f(1/2)
f(3/2) = 1/2*√π
f(3/2) = √π/2
f(x + 1) = x*f(x)
f(x) = k*x! (função fatorial)
f(1/2) = k*(1/2)! = k*âÏ/2 = âÏ --> k = 2
f(x) = 2*x!
f(3/2) = 2*(3/2)!
(3/2)! = 3âÏ/4
f(3/2) = 2*3âÏ/4 = 3âÏ/2
pronto