can someone help with this? thanks
sec²x = 3 tanx
1 ⁄ cos²x = 3 sinx ⁄ cosx
... as a rule I don't cancel terms on each side of an equation. In this case it
doesn't matter.
(1 ⁄ cos²x) – (3 sinx ⁄ cosx) = 0
(1 – 3 sinx cosx) ⁄ cos²x = 0
1 – 3 sinx cosx = 0
1 – (3 ⁄ 2)2 sinx cosx = 0 ... sin(2A) = 2 sinA cosA
1 – (3 ⁄ 2)sin(2x) = 0
sin(2x) = 2 ⁄ 3
2x = 41.81º, 138.19º, 401.81º, 498.19º
x = 20.9º, 69.1º, 200.9º, 249.1º
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Verified answer
sec²x = 3 tanx
1 ⁄ cos²x = 3 sinx ⁄ cosx
... as a rule I don't cancel terms on each side of an equation. In this case it
doesn't matter.
(1 ⁄ cos²x) – (3 sinx ⁄ cosx) = 0
(1 – 3 sinx cosx) ⁄ cos²x = 0
1 – 3 sinx cosx = 0
1 – (3 ⁄ 2)2 sinx cosx = 0 ... sin(2A) = 2 sinA cosA
1 – (3 ⁄ 2)sin(2x) = 0
sin(2x) = 2 ⁄ 3
2x = 41.81º, 138.19º, 401.81º, 498.19º
x = 20.9º, 69.1º, 200.9º, 249.1º