Algem pode me responder essa Questão ?
Ola Luiz
2*log3(x) = -1
log(x) = -log(3)/2
log1/9(x) = -log(x)/log(9) =
-log(x)/2log(9) = log(3)/(2*2log(3)) = 1/4
pronto
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Answers & Comments
Ola Luiz
2*log3(x) = -1
log(x) = -log(3)/2
log1/9(x) = -log(x)/log(9) =
-log(x)/2log(9) = log(3)/(2*2log(3)) = 1/4
pronto