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Note that cos(A) - cos(B) = -2*sin[(A+B)/2]*sin[(A-B)/2].
Then,
cos(π/11) - cos(π/2)
= -2*sin[{(π/11) + (π/2)}/2]*sin[{(π/11) - (π/2)}/2]
= -2*sin(13π/44)*sin(-9π/44)
= 2*sin(13π/44)*sin(9π/44)
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Verified answer
Note that cos(A) - cos(B) = -2*sin[(A+B)/2]*sin[(A-B)/2].
Then,
cos(π/11) - cos(π/2)
= -2*sin[{(π/11) + (π/2)}/2]*sin[{(π/11) - (π/2)}/2]
= -2*sin(13π/44)*sin(-9π/44)
= 2*sin(13π/44)*sin(9π/44)