Verified answer

Okay... let's start with the variables...

L=length and W=width

You said that L = 2 + 3W

You know a square has equal sides... (Change above equation to reflect what you'd do to make it a square. Minus 7 units to length, add 5 from width.)

L - 7 = 2 + 3W + 5

L = 2 + 3W + 5 + 7 = 3W + 14

It's still is a square at this point... so recreate the rectangle. (Add 7 units to length, minus 5 from width.)

L + 7 = 3(W - 5) + 14

L = 3W - 15 + 14 - 7= 3W - 8

So the length of the rectangle should be:

L = 3W - 8

Did this help? (I had to double-check my work...)

Assume the width =x

Length is 2 more than 3 times the width so it is = 3x +2

The square is defined as width =length

so the length of the square here is 3x +2 - 7 and width is x + 5

so the final equation is

3x +2-7 =x +5

so x = 5

The width of the original rectangle is 5

the length of original rectangle is 3 x 5 + 2 = 17

For rectangle, l + 2 = 3w

Since the second is a square, the final length equals the final width, or l - 7 = w + 5

Solve the second one for w by subtracing 5 from both sides to get w = l - 7 - 5 or w = l - 12. Now plug that into the first equatiion, l + 2 = 3w or l + 2 = 3(l - 12) = 3l - 36. Subtract l from each side, then add 36 to each side, to get 38 = 2l or l = 19. Since l - 7 = w + 5 you get 19 - 7 = w + 5 or 12 = w + 5 or w = 7.

a square is wen the length and width r the same. so that means the equation has to be the same.

w=width=x

3x+2=length

if L-7, x+5. equals a square

so. using x and 3x+2 (l and w) plug it into the equation

(3x+2)-7 = x+5

solve for x

Hope It Helps!

L = 3B+2

L-7 = 3B-5

so, 3B-5=B+5, B=2

length of the rectangle is 12