Hola
solucionas
x^2 + 3 x - 4 = 0
Las raíces x1, x2
forman el factoreo
(x - x1) (x - x2)
FÓRMULA ECUACIÓN CUADRÁTICA INCOMPLETA
x₁;x₂ = { -(p) ± √[(p)² - 4(q)] }/(2)
x₁;x₂ = { -(3) ± √[(3)² - 4(-4)] }/(2)
x₁;x₂ = { -3 ± √[9 + 16] }/(2)
x₁;x₂ = { -3 ± √[25] }/(2)
x₁;x₂ = { -3 ± 5 }/(2)
Dos soluciones
Primera solución
x1 = (-3-5)/2 = -8/2 = -4
Segunda solución
x2 = (-3+5)/2 = 2/2 = 1
Factoreo
(x -(-4))(x - 1) = 0
ó
(x + 4) (x - 1) = 0
***********
x²+3x-4=0
(x+4)(x-1)=0
x+4=0 --> x=-4
x-1=0 ---> x=1
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Answers & Comments
Hola
solucionas
x^2 + 3 x - 4 = 0
Las raíces x1, x2
forman el factoreo
(x - x1) (x - x2)
FÓRMULA ECUACIÓN CUADRÁTICA INCOMPLETA
x₁;x₂ = { -(p) ± √[(p)² - 4(q)] }/(2)
x₁;x₂ = { -(3) ± √[(3)² - 4(-4)] }/(2)
x₁;x₂ = { -3 ± √[9 + 16] }/(2)
x₁;x₂ = { -3 ± √[25] }/(2)
x₁;x₂ = { -3 ± 5 }/(2)
Dos soluciones
Primera solución
x1 = (-3-5)/2 = -8/2 = -4
Segunda solución
x2 = (-3+5)/2 = 2/2 = 1
Factoreo
(x -(-4))(x - 1) = 0
ó
(x + 4) (x - 1) = 0
***********
x²+3x-4=0
(x+4)(x-1)=0
x+4=0 --> x=-4
x-1=0 ---> x=1