(1 + √2)² = 1 + 2 + 2√2 = 3 + 2√2
(3 + 2√2)² = 9 + 8 + 12√2 = 17 + 12√2
pronto
(1+â 2)^4 = 17 + 12â 2
(1+â2)^4 = 1 + 4*1*â2 + 6*1*â2^2 + 4*1*â2^3 + 1*â2^4
. . . . . . . = 1+ 4â2 + 12 + 8â2 + 4
. . . . . . . = 17 + 12â2
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Verified answer
(1 + √2)² = 1 + 2 + 2√2 = 3 + 2√2
(3 + 2√2)² = 9 + 8 + 12√2 = 17 + 12√2
pronto
(1+â 2)^4 = 17 + 12â 2
(1+â2)^4 = 1 + 4*1*â2 + 6*1*â2^2 + 4*1*â2^3 + 1*â2^4
. . . . . . . = 1+ 4â2 + 12 + 8â2 + 4
. . . . . . . = 17 + 12â2