Pure R isomer has a specific rotation of –154.0°, and a sample contains 82.0% of R isomer and 18.0%?
If a pure R isomer has a specific rotation of –154.0°, and a sample contains 82.0% of the R isomer and 18.0% of its enantiomer, what is the observed specific rotation of the mixture?
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If the R isomer has a specific rotation of -154.0° then the S isomer has a rotation of +154.0°. The rotation observed for an R/S mixture is additive: (I'll work in %.)
[-154.0×82.0 + 154.0×18.0]/100 = -98.6° (three sig figs)