Calculate the amount of heat released to change 85g of water to ice at 0∘C.?
47) Calculate the amount of heat released to change 85g of water to ice at 0∘C.
48) Calculate the amount of heat released when 65.0g of water at 66.5∘C cools to ice at 0.0 ∘C.
Express your answer to three significant figures and include the appropriate units.
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47) First, look up the heat of fusion for water. Then heat = mass of water (85 g) x the heat of fusion. If the heat of fusion is given as the molar heat of fusion, convert the 85 g to moles (85/18 = 4.72 moles) and multiply that by the molar heat of fusion. There is no ∆T as there is only a phase change.
48) q = mC∆T = (65 g)(4.18 J/g/deg)(66.5 deg) = 18,068 J or 18.1 kJ