Is this written properly?
However, we do have
∫(t = 0 to 1) sin^2(πt) dt
= ∫(t = 0 to 1) (1/2)(1 - cos(2πt)) dt
= (1/2)(w - sin(2πt)) {for t = 0 to 1}
= 1/2.
I hope this helps!
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Verified answer
Is this written properly?
However, we do have
∫(t = 0 to 1) sin^2(πt) dt
= ∫(t = 0 to 1) (1/2)(1 - cos(2πt)) dt
= (1/2)(w - sin(2πt)) {for t = 0 to 1}
= 1/2.
I hope this helps!