please help me prove this identity and show all steps:
( cot 240° tan 240°)/(sin 240°)= csc°
Since cot 240 = 1 / tan 240,
cot 240 x tan 240 = 1.
Hence,
given expression = 1 / sin 240 = csc 240.
........................................................................................
FYI
..................
sin 240 = sin ( 180 + 60 ) = sin 60 = ( sqrt 3 ) / 2
so that
csc 240 = 1 / sin 240 = 1 / ( sqrt 3)/2 = 2 / ( sqrt 3 ).
Happy To Help !
csc 240º = 1/sin 240º
cot 240º = 1/tan 240º
So,
(cot 240° tan 240°)/(sin 240°) = csc 240°
((1/tan 240º) * tan 240º)/sin(240º) = 1/sin 240º
1/sin 240º = 1/sin 240º
QED
cot and tan are reciprocals so the numerator =1:
1/sin240 =csc240
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Verified answer
Since cot 240 = 1 / tan 240,
cot 240 x tan 240 = 1.
Hence,
given expression = 1 / sin 240 = csc 240.
........................................................................................
FYI
..................
sin 240 = sin ( 180 + 60 ) = sin 60 = ( sqrt 3 ) / 2
so that
csc 240 = 1 / sin 240 = 1 / ( sqrt 3)/2 = 2 / ( sqrt 3 ).
........................................................................................
Happy To Help !
csc 240º = 1/sin 240º
cot 240º = 1/tan 240º
So,
(cot 240° tan 240°)/(sin 240°) = csc 240°
((1/tan 240º) * tan 240º)/sin(240º) = 1/sin 240º
1/sin 240º = 1/sin 240º
QED
cot and tan are reciprocals so the numerator =1:
1/sin240 =csc240