Problem 6. (15 pts) Hess Law application: from the enthalpies of reaction: H2(g) + F2(g) 2HF (g) ΔH = -?
Problem 6. (15 pts) Hess Law application: from the enthalpies of reaction:
H2(g) + F2(g) 2HF (g) ΔH = -537 kJ
C(s) + 2F2(g) CF4(g) ΔH = -680 kJ
2 C(s) + 2 H2(g) C2H4(g) ΔH = +52.3 kJ
Calculate ΔH for the following reaction:
C2H4(g) + 6F2(g) 2 CF4(g) + 4HF(g)
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Verified answer
multiply first by 2
multiply second by 2
flip third
2H2(g) + 2F2(g) ---> 4HF (g) ΔH = -1074 kJ
2C(s) + 4F2(g) ---> 2CF4(g) ΔH = -1360 kJ
C2H4(g) ---> 2 C(s) + 2 H2(g) ΔH = -52.3 kJ
Add the three equations together to yield the target equation. Add the three enthalpies for the ΔH of the reaction.
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http://www.chemteam.info/Thermochem/HessLawIntro1a...
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