02.Interpole 4 meio aritméticos entre -12 e 48.
03.Quantos são multiplos de 4 entre 101 e 3001.
Obg!
1)a2=9
a14=45
45=a1+13r
9=s1+r
45-9=13r-r
36=12r
r=36/12
r=3
2)48=-12+5r
48+12=5r
5r=60
r=60/58
r=12
(-12,0,12,24,36,48)
3)300=104+(n-1)4
300=104+4n-4
300=100+4n
300-100=4n
4n=200
n=200/4
n=50 míltiplos
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Verified answer
1)a2=9
a14=45
45=a1+13r
9=s1+r
45-9=13r-r
36=12r
r=36/12
r=3
2)48=-12+5r
48+12=5r
5r=60
r=60/58
r=12
(-12,0,12,24,36,48)
3)300=104+(n-1)4
300=104+4n-4
300=100+4n
300-100=4n
4n=200
n=200/4
n=50 míltiplos