Pre-Calc Questions find 2θ(theta)?
Find 2Θ given cosΘ =-3/5 B= π/5 and sinΘ >0
i don't understand the question or how to find it=/
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Find 2Θ given cosΘ =-3/5 B= π/5 and sinΘ >0
i don't understand the question or how to find it=/
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I am not quite sure about B= π/5 is for...
since cosΘ =-3/5 and sinΘ >0, so we may know Θ is in the 2nd quadrant.
cos 2Θ = 2 cos^2Θ - 1 = 2 (-3/5)^2 - 1 = -7/25
2Θ = Arc(cos(-7/25)) = 106.26 degrees