P≠Q Math help puhlease?
If p≠q and p(q+q) = qx-s, then x=
Answer is pq+s/q-p but not sure how it gets there
Someone please explain step by step.
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If p≠q and p(q+q) = qx-s, then x=
Answer is pq+s/q-p but not sure how it gets there
Someone please explain step by step.
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Verified answer
p(q+q) = qx-s
2pq = qx - s
2pq + s = qx
(2pq + s)/q = x
2p + s/q = x
p(q + q) = qx - s
distribute the p
pq + pq = qx - s
simplify by adding both pq together
2pq = qx - s
get the qx alone by adding s to both sides
2pq + s = qx
divide by q
(2pq + s)/q = x
simplify
2p + s/q = x