PLEASE HELP Two particles with Q1 =45 µC and Q2 = 85 µC are initially separated by a distance of 2.5 m?
Two particles with Q1 =45 µC and Q2 = 85 µC are initially separated by a distance of 2.5 m and then brought closer together so that the final separation is 1.5 m. What is the change in the electric potential energy?
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Ep = k * Q1 * Q2 / R
where
Ep = potential energy = ?
k = Coulomb's constant = 8.987E9 Nm²/C²
Q1 = charge 1 = 45E-6 C
Q2 = charge 1 = 85E-6 C
R = distance between Q1 and Q2 = 2.5 m or 1.5 m
When R = 2.5 m, then
Ep = 8.987E9 * 45E-6 * 85E-6 / 2.5 = 13.75 J
When R = 1.5 m, then
Ep = 8.987E9 * 45E-6 * 85E-6 / 2.5 = 22.92 J
The change is
22.92 - 13.75 = 9.17 J