Please help The charge per unit length on a glass rod is λ= -7.5 µC/m. If the rod is 2.5 m long?
The charge per unit length on a glass rod is λ= -7.5 µC/m. If the rod is 2.5 m long, how many excess electrons are on the rod?
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by q = λ x L
=>q = -7.5 x 10^-6 x 2.5
=>q = -18.75 x 10^-6 C
by q = ne
=>-18.75 x 10^-6 = n x (-1.6 x 10^-19)
=>n = 1.17 x 10^14