PLEASE HELP ROGER THE MOLE Sodium thiosulfate (photographer’s hypo) reacts with unexposed silver bromide?
Sodium thiosulfate (photographer’s hypo) reacts
with unexposed silver bromide in film
emulsion to form sodium bromide and a soluble
compound of formula Na3[Ag(S2O3)2]:
2 Na2S2O3(aq) + AgBr(s) →
NaBr(aq) + Na3[Ag(S2O3)2](aq)
How many moles of Na2S2O3 are needed to
react with 8.5 mg of AgBr?
Answer in units of mol.
PART 2
Calculate the mass of silver bromide that will
produce 0.027 mol Na3[Ag(S2O3)2].
Answer in units of g.
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Verified answer
(8.5 × 10^-3 g AgBr) / (187.7722 g AgBr/mol) × (2 mol Na2S2O3 / 1 mol AgBr) = 9.1 × 10^-5 mol Na2S2O3
PART 2:
(0.027 mol Na3[Ag(S2O3)2]) x (1 mol AgBr / 1 mol Na3[Ag(S2O3)2]) x (187.7722 g AgBr/mol) = 5.1 g AgBr