Verified answer

1/(t + √(t² + 1)) =

(t - √(t² + 1))/((t + √(t² + 1)*(t - √(t² + 1))) =

(t - √(t² + 1))/(t² - (t² + 1)) =

(t - √(t² + 1)/(-1) = √(t² + 1) - t

pronto

1(t-Vt²+1):[(t-Vt²+1)(t+Vt²+1)]

1(t-Vt²+1):[t²-(Vt²+1)²]=

(t-Vt²+1):(t²-t²+1)=

(t-Vt²+1):1=

t-Vt²+1

. . . 1 . . . . .. .(t - √t^2+1 ) . . .(t - √t^2+1 ) . . .(t - √t^2+1 )

-------------- x --------------- = ------------------ = ---------------- = - t + √t^2+1 )

t + √t^2+1 . .(t - √t^2+1 ) . . . t^2 - (t^2+1) . . . . . -1

eek