It is (x+1)(x+1) or (x+1)^2
-
x² + 2x + 1 = ( x + 1 ) ( x + 1 ) = ( x + 1 ) ²
x² + 2x + 1
= (x + 1)²
What are two numbers that multiply to be 1, but add to be 2?
Hint:
1 × 1 = 1
1 + 1 = 2
So it's pretty obvious how to factor this:
(x + 1)(x + 1)
But those terms are the same, so you can just write the binomial once, but squared.
Answer:
(x + 1)²
P.S. Learn to recognize the squared binomial:
(a + b)² = a² + 2ab + b²
In your case, the first and last terms are squares:
x² = x * x
1 = 1 * 1
And the middle term is double the product:
2 * x * 1 = 2x
So just by recognizing the form, you should be able to directly see that's a squared binomial.
x^2 + 2x + 1 =
(x + 1)^2
x^2 + 2x + 1
= (x + 1)^2
(x+1)^2 .... ... . . . .
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Verified answer
It is (x+1)(x+1) or (x+1)^2
-
x² + 2x + 1 = ( x + 1 ) ( x + 1 ) = ( x + 1 ) ²
x² + 2x + 1
= (x + 1)²
What are two numbers that multiply to be 1, but add to be 2?
Hint:
1 × 1 = 1
1 + 1 = 2
So it's pretty obvious how to factor this:
(x + 1)(x + 1)
But those terms are the same, so you can just write the binomial once, but squared.
Answer:
(x + 1)²
P.S. Learn to recognize the squared binomial:
(a + b)² = a² + 2ab + b²
In your case, the first and last terms are squares:
x² = x * x
1 = 1 * 1
And the middle term is double the product:
2 * x * 1 = 2x
So just by recognizing the form, you should be able to directly see that's a squared binomial.
x² + 2x + 1
= (x + 1)²
x^2 + 2x + 1 =
(x + 1)^2
x^2 + 2x + 1
= (x + 1)^2
(x+1)^2 .... ... . . . .