One mole of an ideal gas initially at a temperature of 1.30 102 °C is compressed at a constant pressure of 2.00 atm to two-thirds its initial volume.
(a) What is the final temperature of the gas?
K
(b) Calculate the work done on the gas during the compression.
J
Update:Please show work
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Verified answer
(a)
(V1)/(T1) = (V2)/(T2)
V / (130 + 273K) = (2/3)V / (T2)
T2 = (2/3)(403K)
T2 = 269K
(b)
W = -nRΔT
W = -(1 mol)(8.314 J/mol-K)(269 - 403K)
W = 1114 J
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